Not true. Why does a siphon work? The weight of the water going down to the pump is equvalent to the the weight of the water going out of the pump! This cancels out the "Head Loss" and the only head loss in a closed loop system is due to the friction of the water going through the pipes, which is proportional to the distance of the pipes and inversely proportional to the square of the diameter of the pipe, roughly. Bends complicate things a bit.
Think of it this way: The potential energy of the water is not changed, only the kinetic energy.
In a sump system, the water flowing into the sump looses potential energy (turned into kinetic as it accelerates into the sump) which is lost by the time the water is sucked into the return pump.
Its like a car (engine off) at the top of a hill. When it goes down a hill, it gathers speed (accelerates) and if there is a second, equally high hill, it will go up the hill (almost, due to energy lost to friction). If you want to go all the way up the hill, you need a motor (like the pump in a closed loop) to overcome the friction. The energy used to overcome friction is the same energy used to propell the car and equivalent distance on a flat surface!
This is physics 101 stuff here.
Interestingly enough the position of the intake and exhaust in a closed loop system makes no difference to the head pressure issue as long as both are under the surface of the water.
I know that it sounds a bit counter-intuitive, but it is fact.