another reason not use Rio Pumps

[Deanos]

Can someone explain why hobbyists frequently report lower tank temperatures when switching to a more efficient submersible pump?

 

[Wes]

Can someone explain why hobbyists frequently report lower tank temperatures when switching to a more efficient submersible pump?

because a more efficient pump can move the same amount of water using less energy

 

[Awibrandy]

can someone look at the 2 pics, and tell me if that is the issue with the rios please?

 

[Psycho graphic]

Awibrandy, I have never owned a Rio because of all the failures I've read about, but everytime I have read of one failing, the epoxy that encloses the windings has cracked (probably due to heat) exposing the copper windings. You might want to take it apart to see if that has happened to yours. Unplugged of coUrse!

 

[Awibrandy]

Thank you Psycho graphic..

 

[nyfireman3097]

just wondering my RD return pump I can touch in the tank and feel like it is if it were off for 24 hours how is that producing heat into the water ?
TIA

 

[Chiefmcfuz]

LOL The firefighters will get a kick out of this one from MPO school, unless they've changed the way they teach it different.

18!!

 

[nyfireman3097]

????

 

[cali_reef]

:lol2:

 

[Wes]

http://www.reefcentral.com/forums/showthread.php?s=&threadid=833695

 

[Aqua Pro Builder]

any submersible pump that uses the same wattage is going to heat the water the same amount...Regardless of how good it is..

Law of Conservation of Energy

Disagreed!!!

It depends on the efficiency of the pumps. Some pumps convert more energy to the mechnical moving while some convert more to heat. Look at the traditional light bulbs vs the flourescent light bulbs, same amount of power consumption does not yield same amount of light nor heat. They all obey the Law of Conservation of Energy.

NOTE: WES, I may have to take back what I just said because I see your word "use" same amount of watt. I'll have to rethink it over before rejoin you with this discussion.

After some re-thinking, the close looped water circulation and that the pump is within the closed loop being sub-merged do seem to give your thoery credits. But I still need more time to consider if there are other major venues(small ones don't count such as sound ...) of energy escaping. I want to find out why most reefers find that they have lower temperatures after they switched to a more effective pump. I have to compare the two scenarios to make sure we are not missing something somewhere. If you can point out why, I guess a lot of us would understand better.

More Note: Wes, pumping and lighting really are not good analogies of each other, they very different systems. Sorry my bad.

 

[Wes]

Disagreed!!!

It depends on the efficiency of the pumps. Some pumps convert more energy to the mechnical moving while some convert more to heat. Look at the traditional light bulbs vs the flourescent light bulbs, same amount of power consumption does not yield same amount of light nor heat. They all obey the Law of Conservation of Energy.

sigh....i give up on trying to teach science to everyone...you are wrong on the pumps and the light thing...

read this thread and get back to me...

http://www.reefcentral.com/forums/showthread.php?s=&threadid=833695

 

[ming]

According to your theory, everything becomes heat so long as its drawing the same amount of watts. So what if you had a 50W pump and took the impeller out but still plugged in the wall socket? It doesn't need a impeller for the pump to use electric. Would it heat the water as much as a 50W heater? I can leave the pump on, and turn the heater to its max so it stays on. This would be a very accuate test because both items are not moving any water, and both are drawing the same amount of electric. So technically, both are 50W heaters, according to your logic.

 

[Wes]

According to your theory, everything becomes heat so long as its drawing the same amount of watts. So what if you had a 50W pump and took the impeller out but still plugged in the wall socket? It doesn't need a impeller for the pump to use electric. Would it heat the water as much as a 50W heater? I can leave the pump on, and turn the heater to its max so it stays on. This would be a very accuate test because both items are not moving any water, and both are drawing the same amount of electric. So technically, both are 50W heaters, according to your logic.

yes ming that model should give give you the same results since you are removing the the increased evaporation via surface agitation from the equation...you would have to have both plugged into a kill-o-watt to ensure they both draw the same amount of energy for the length of your study.

 

[Deanos]

http://www.reefcentral.com/forums/showthread.php?s=&threadid=833695

Great thread . A lot of bickering there too. :redface: However, all I got out of it was that both a heater and pump of the same wattage will add the same amount of "heat energy" to the water; but due to increased water movement caused by the pump, the water's temperature will not rise as high as the heater's water because of evaporative cooling. Ultimately that's what a reefkeeper is interested in...the water's temperature at any given point.