another reason not use Rio Pumps

[Awibrandy]

Ambiant room temp. 62 degrees, temp. in mixing rubbermaid container without a heater 80 degrees.

 

[Deanos]

What about other brands? My Mag drive pump does the same thing. We need comparisons to how much other pumps heat the water, before writing off the Rio for that reason.

 

[marrone]

My Mag pumps gives off a lot more heat than my Rio Pumps, while my Eheim pumps run a lot more cooler.

 

[Awibrandy]

What about other brands? My Mag drive pump does the same thing. We need comparisons to how much other pumps heat the water, before writing off the Rio for that reason.

Deano I would agree with you. Except that I stated that it's just another reason. Meaning, that along with all the horror stories I've been reading about the rios now I have another reason why to ditch them. Their good for mixing my water thou. I don't have to add a heater:lol_large to my mxing container, which in turn saves me electricity...

Marrone, funny you should post this. I am replacing my rio in my fowlr with an eheim.. Thanks for comfirming.

 

[Deanos]

Their good for mixing my water thou. I don't have to add a heater:lol_large to my mxing container, which in turn saves me electricity...

Wouldn't this make it a reason to use a Rio? :scratch:

 

[inline6]

Could these pumps have electrical leakage problems?
Mine never get hot, however I use Maxijets and SEIOs to mix new water.

 

[Awibrandy]

Wouldn't this make it a reason to use a Rio? :scratch:

In a mixing container yes. But not in the tanks. If the pump goes bad in a mixing container, I'll just dump it. No big loss. But if it goes bad in the tank there is a great deal of loss. Especially that of live..

Inline, I have all these extra pumps that I removed from my systems that are still working, so why not put them to use until they do go?

 

[scarf_ace1981]

i use my rio to mix and heat my ro. :biggrin:

 

[num]

i had that problem once and all i did was put a fan in the fand to pull the heat out

 

[Wes]

any submersible pump that uses the same wattage is going to heat the water the same amount...Regardless of how good it is..

Law of Conservation of Energy

 

[Deanos]

any submersible pump that uses the same wattage is going to heat the water the same amount...Regardless of how good it is..

Law of Conservation of Energy

:hug:

 

[NYreefNoob]

Rio Pumps

i currently have 2 rio's in my tank. a 2100 and a 800 and havent had any problems with mine, failure heat or anything. no temps spikes or raise's. and these 2 pumps are in a 29g tank

 

[Awibrandy]

i currently have 2 rio's in my tank. a 2100 and a 800 and havent had any problems with mine, failure heat or anything. no temps spikes or raise's. and these 2 pumps are in a 29g tank

I had rio3100,2100,1800,and 2 600 in my tanks for years without any problems either. I've read so many horror stories that I decided to take them out before they exploded and killed everything. I found out about the heat thing while making water in a 30gl.rubbermaid trash can in my downstairs bathroom which has no heat. The ambient temp in this room is 62, and the water in the can is 80.
I don't know that my pumps would ever fail, but at this point I'd rather take precaution.

 

[Wes]

like i said before it doesn't matter what pump you use...Watts are Watts...

Whether it be a 50watt Rio, a 50watt eheim, or a 50 watt Heater...They are all going to heat your water the same amount.

you would only see difference in heat by switching pumps if you use a pump that uses less energy...

 

[meschaefer]

any submersible pump that uses the same wattage is going to heat the water the same amount...Regardless of how good it is..

Law of Conservation of Energy

Your misconstruing the law of conservation of energy. The amount of heat that a pump puts out is based on its efficiency. Primarily the pump uses the energy to move water (kinetic energy ?), not to turn the electrical energy into heat energy. The law of conservation of energy would state the following, in very simplified form

water movenment (Kinetic energy) + Heat = watts used.

In theory, a competley efficent pump will put out no heat (granted there are no completely efficient pumps), i.e the kinetic energy of the water leaving the pump will equal the amount of energy that the pump is drawing.

If you have two pumps using 90 watts, and one pumps 600 gallons per hour, and one pumps 800 gallons per hour (i.e it has more kinetic energy), the 600 gallon per hour is going to put out more heat than the other as it is pumping less water (kinetic energy) so the energy needs to go somewhere (i.e heat energy).

 

[Deanos]

If you have two pumps using 90 watts, and one pumps 600 gallons per hour, and one pumps 800 gallons per hour (i.e it has more kinetic energy), the 600 gallon per hour is going to put out more heat than the other as it is pumping less water (kinetic energy) so the energy needs to go somewhere (i.e heat energy).

:idea::thanks:

 

[cali_reef]

like i said before it doesn't matter what pump you use...Watts are Watts...

Whether it be a 50watt Rio, a 50watt eheim, or a 50 watt Heater...They are all going to heat your water the same amount.

you would only see difference in heat by switching pumps if you use a pump that uses less energy...

Not true at all..

 

[inline6]

Man, how did this simple problem get sooo technical?
Do whatever works for you.
Personally I never had a problem w/pumps heating up my water, in fact I have to add a heater to get the right temp.

 

[meschaefer]

Man, how did this simple problem get sooo technical?
Do whatever works for you.
Personally I never had a problem w/pumps heating up my water, in fact I have to add a heater to get the right temp.

This is not a big problem, but can be in the summer. Alot of people have trouble with tank temps in the summer.

 

[Wes]

Your misconstruing the law of conservation of energy. The amount of heat that a pump puts out is based on its efficiency. Primarily the pump uses the energy to move water (kinetic energy ?), not to turn the electrical energy into heat energy. The law of conservation of energy would state the following, in very simplified form

water movenment (Kinetic energy) + Heat = watts used.

In theory, a competley efficent pump will put out no heat (granted there are no completely efficient pumps), i.e the kinetic energy of the water leaving the pump will equal the amount of energy that the pump is drawing.

If you have two pumps using 90 watts, and one pumps 600 gallons per hour, and one pumps 800 gallons per hour (i.e it has more kinetic energy), the 600 gallon per hour is going to put out more heat than the other as it is pumping less water (kinetic energy) so the energy needs to go somewhere (i.e heat energy).

you are oversimplifying it...

The kinetic energy eventually becomes heat via friction...if there were no friction there would be no need for a pump to keep the water movement...

a more efficient pump will produce more kinetic energy, but that kinetic energy still becomes heat...

both pumps will reach the same steady state of heating the water, in other words, the more efficient pump will take longer to heat the water, but they will both heat the water to the same degree...

trust me i know my stuff